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A line passes through the points (-6,-5) and (-8,-7). What is the equation of this line in slope intercept form?

Respuesta :

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -6 &,& -5~) % (c,d) &&(~ -8 &,& -7~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-7-(-5)}{-8-(-6)} \\\\\\ \cfrac{-7+5}{-8+6}\implies \cfrac{-2}{-2}\implies 1[/tex]

[tex]\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=1[x-(-6)] \\\\\\ y+5=1(x+6)\implies y+5=x+6\implies y=x+1[/tex]

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