The gas in a cylinder has a volume of 3 liters at a pressure of 117 kpa. the pressure of the gas is increased to 219 kpa. assuming the temperature remains constant, what would the new volume be?

Respuesta :

V = (1 / p) × p0×V0 = (1 / 219kPa) × 117kPa × 3L = 1.06L