NERDYinsomecases
NERDYinsomecases
03-02-2017
Mathematics
contestada
GEOMETRY. image attached
Respuesta :
jdoe0001
jdoe0001
03-02-2017
[tex]\bf \measuredangle DFC=\cfrac{1}{2}(\widehat{BG}+\widehat{CD})\implies \measuredangle DFC=\cfrac{\widehat{BG}+\widehat{CD}}{2}[/tex]
you know what the arcCD is, and what the angle DFC is, so
solve for the arcBG
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